0=-1x^2-2x+558

Solution for 0=-1x^2-2x+558 equation:

0=-1x^2-2x+558

We move all terms to the left:

0-(-1x^2-2x+558)=0

We add all the numbers together, and all the variables

-(-1x^2-2x+558)=0

We get rid of parentheses

1x^2+2x-558=0

We add all the numbers together, and all the variables

x^2+2x-558=0

a = 1; b = 2; c = -558;
Δ = b2-4ac
Δ = 22-4·1·(-558)
Δ = 2236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2236}=\sqrt{4*559}=\sqrt{4}*\sqrt{559}=2\sqrt{559}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{559}}{2*1}=\frac{-2-2\sqrt{559}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{559}}{2*1}=\frac{-2+2\sqrt{559}}{2}
$